QQ直接打开域名链接报毒的处理办法-米微资源分享网

用一个不报毒的域名，放入一下代码（PHP）！原理就是利用不报毒域名打开+QQ跳转浏览器 + 跳转到主域名，测试系统：ios、测试域名：cn、top 测试结果：OK。

代码如下：

//直接跳转到指定网址

<?php

$url = "http://www.qzoner.cn";//这里是要跳转的域名

$scriptpath = str_replace('', '/', $_SERVER['SCRIPT_NAME']);
$sitepath = substr($scriptpath, 0, strrpos($scriptpath, '/'));
$siteurl = ($_SERVER['SERVER_PORT'] == '443' ? 'https://' : 'http://') . $_SERVER['HTTP_HOST'] . $sitepath . '/';
if (strpos($_SERVER['HTTP_USER_AGENT'], 'QQ/') !== !1 ) {
echo '<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>请使用浏览器打开</title>
<script src="https://open.mobile.qq.com/sdk/qqapi.js?_bid=152"></script>
<script type="text/javascript"> mqq.ui.openUrl({ target: 2,url: "' . $url . '"}); </script>
</head>
<body></body>
</html>';
exit;
}else{
echo "<script type='text/javascript'>";
echo "window.location.href='$url'";
echo "</script>";
}
?>

//先用浏览器打开当前域名再做跳转

<?php
$url = "http://www.qzoner.cn";//这里是要跳转的域名
$scriptpath = str_replace('', '/', $_SERVER['SCRIPT_NAME']);
$sitepath = substr($scriptpath, 0, strrpos($scriptpath, '/'));
$siteurl = ($_SERVER['SERVER_PORT'] == '443' ? 'https://' : 'http://') . $_SERVER['HTTP_HOST'] . $sitepath . '/';
if (strpos($_SERVER['HTTP_USER_AGENT'], 'QQ/') !== !1 ) {
echo '<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>请使用浏览器打开</title>
<script src="https://open.mobile.qq.com/sdk/qqapi.js?_bid=152"></script>
<script type="text/javascript"> mqq.ui.openUrl({ target: 2,url: "' . $siteurl. '"}); </script>
</head>
<body></body>
</html>';
exit;
}
echo "<script type='text/javascript'>";
echo "window.location.href='$url'";
echo "</script>";

?>

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